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**CBSE class 11 Computer Science with Python chapter 3, Data Representation in Computers**. You can find the questions/answers/solutions for the**chapter 3**of Unit 1 of**CBSE class 11 Computer Science with Python**in this page.a)

What does ASCII stand for?

b)

What does the base of a Number system mean?

c)

What is the base of Decimal, Binary, Octal and Hexadecimal number systems?

d)

How many digits are there in a Binary number system?

e)

Which digits are used in Hexadecimal number system?

f)

What is Unicode? How is it useful?

g)

Distinguish between ASCII and ISCII.

h)

Do as directed :

●

Convert the Decimal number 781 to its Binary equivalent.

●

Convert Binary number 101101.001 to its decimal equivalent

●

Convert Octal number 321.7 into its Binary equivalent

●

Convert the Hexadecimal number 3BC into its Binary equivalent

●

Convert the Binary number 10011010.010101 to its Hexadecimal equivalent

●

Convert the Decimal number 345 into Octal number.

●

Convert the Decimal number 736 into Hexadecimal number.

●

Convert the Octal number 246.45 into Hexadecimal number.

●

Convert the Hexadecimal number ABF.C into Octal number.

●

Convert the Octal number 576 to Decimal.

●

Convert the Hexadecimal number A5C1 to Decimal.

Data Representation in Computers

a) What does ASCII stand for?

ASCII is an acronym for American Standard Code for Information Interchange. ASCII-7 uses a total of 7 bits of which 4 are zone bits and 3 are numeric bits and can represent 128 characters. ASCII-8 is an extension of ASCII-7 and can represent 256 characters.

b) What does the base of a Number system mean?

The base of a Number system, also called as radix, is the number of unique digits that are used to represent the numbers in a positional number system. The number of unique digits includes the digit zero (0) also. For instance, the binary system is represented by the digits 0 and 1 (Two numbers are used and hence the name binary). The octal system uses 0, 1, 2, 3, 4, 5, 6 and 7 (total of eight numbers and hence the name octal) to represent the numbers. The decimal system uses 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 (total of 10 digits and hence the name) to represent the numbers. The hexadecimal system uses 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F (total of 16 numbers and hence the name hexadecimal) to represent the numbers.

c) What is the base of Decimal, Binary, Octal and Hexadecimal number systems?

The following are the bases of the various number systems.

Number System

Base or Radix

Decimal System

10

Binary System

2

Octal System

8

Hexadecimal System

16

d) How many digits are there in a Binary number system?

There are two digits i.e. 0 and 1 in the binary number system.

e) Which digits are used in Hexadecimal number system?

The digits (to be specific it is a combination of digits and alphabets) used in the Hexadecimal number system are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F. In this A represents 10, B represents 11, C represents 12, D represents 13, E represents 14 and F represents 15.

f) What is Unicode? How is it useful?

Definition:

Unicode is a new coding standard or character encoding system, promoted by Unicode Consortium. This new Unicode standard is adopted by all new platform. Unicode provides a unique number for every character. This unique number will be the same on all the platforms, programs and the languages.

Unicode is a new coding standard or character encoding system, promoted by Unicode Consortium. This new Unicode standard is adopted by all new platform. Unicode provides a unique number for every character. This unique number will be the same on all the platforms, programs and the languages.

Use:

1.

Unicode makes it possible to support the worldwide interchange, processing and display of the written text of the diverse languages.

2.

Due to this the support for various languages is provided.

3.

It is now possible to interchange data between different platforms.

g) Distinguish between ASCII and ISCII.

The following is the differentiation between ASCII and ISCII.

Basis

ASCII

ISCII

1. Full Form

Acronym for American Standard Code for Information Interchange

Acronym for Indian Standard Code for Information Interchange

2. Standard

This is an American Standard.

This is Indian Standard.

3. No. of Variations

Has two variations ASCII-7 and ASCII-8

Has only one variation.

4. No. of Characters

Has either 128 characters (in ASCII-7) or 256 characters (in ASCII-8)

Represents a larger set of characters

5. Representation Range

Has limited representation of characters.

Allows representation of English and Indian scripts simultaneously.

6. No. of Bits used

ASCII-7 used 7 bits and ASCII-8 used 8 bits to represent the characters

Uses 8 bits to represents the characters.

7. Supported Characters

Supports English and other Latin characters

Supports English and Indian Scripts

h) Do as directed :

●

Convert the Decimal number 781 to its Binary equivalent.

●

Convert Binary number 101101.001 to its decimal equivalent

●

Convert Octal number 321.7 into its Binary equivalent

●

Convert the Hexadecimal number 3BC into its Binary equivalent

●

Convert the Binary number 10011010.010101 to its Hexadecimal equivalent

●

Convert the Decimal number 345 into Octal number.

●

Convert the Decimal number 736 into Hexadecimal number.

●

Convert the Octal number 246.45 into Hexadecimal number.

●

Convert the Hexadecimal number ABF.C into Octal number.

●

Convert the Octal number 576 to Decimal.

●

Convert the Hexadecimal number A5C1 to Decimal.

Convresion of Decimal number 781 to its Binary equivalent.

Quotient

Remainder

{\dfrac{781}{2} = 390}

1

{\dfrac{390}{2} = 195}

0

{\dfrac{390}{2} = 97}

1

{\dfrac{97}{2} = 48}

1

{\dfrac{48}{2} = 24}

0

{\dfrac{24}{2} = 12}

0

{\dfrac{12}{2} = 6}

0

{\dfrac{6}{2} = 3}

0

{\dfrac{3}{2} = 1}

1

{\dfrac{1}{2} = 0}

1

∴ (781)

_{10}= (1100001101)_{2}Conversion Binary number 101101.001 to its decimal equivalent.

101101.0012

=

(1 × 2

^{5})+

(0 × 2

^{4})+

(1 × 2

^{3})+

(1 × 2

^{2})+

(0 × 2

^{1})+

(1 × 2

^{0})+

(0 × 2

^{-1})+

(0 × 2

^{-2})+

1 × 2

^{-3}=

32

+

0

+

8

+

4

+

0

+

1

+

0

+

0

+

0.125

= (45.125)

_{10}∴ (101101.001)2 = (45.125)

_{10}Convertion of Octal number 321.7 into its Binary equivalent

3

2

1

.

7

011

010

001

.

111

∴ (321.7)

_{7}= (11010001.111)_{2}Note: Instead of 011010001.111, we’ve written this as 11010001.111 as zero in the beginning need not be considered.

Conversion of the Hexadecimal number 3BC into its Binary equivalent

3

B

C

0011

1011

1100

∴ (3BC)

_{16}= (1110111100)_{2}Note: Instead of 001110111100, we’ve written this as 1110111100 as zero in the beginning need not be considered.

Conversion of the Binary number 10011010.010101 to its Hexadecimal equivalent

1001

1010

.

0101

0100

9

A

.

5

4

∴ (10011010)

_{2}= (9A.54)_{16}Note The last column is added with two zeros and splitted as 0100 instead of simply 01 to ensure that there are four binaries at the end.

Convert the Decimal number 345 into Octal number.

Quotient

Remainder

{\dfrac{345}{8} = 43}

1

{\dfrac{43}{8} = 5}

3

{\dfrac{5}{8} = 0}

5

∴ (345)

_{10}= (531)_{8}Conversion of the Decimal number 736 into Hexadecimal number.

Quotient

Remainder

{\dfrac{736}{16} = 46}

0

{\dfrac{46}{16} = 2}

14 = E

{\dfrac{2}{16} = 0}

2

∴ (736)

_{10}= (2E0)_{16}Conversion of the Octal number 246.45 into Hexadecimal number.

Octal

2

4

6

.

4

5

3-Bit Binary

010

100

110

.

100

101

4-Bit Binary

0000

1010

0110

.

1001

0100

Hexadecimal

0

A

6

.

9

4

∴ (246.45)

_{8}= (A6.94)_{16}Conversion of the Hexadecimal number ABF.C into Octal number.

Hexadecimal

A

B

F

.

C

4-Bit Binary

1010

1011

1111

.

1100

3-Bit Binary

101

010

111

111

.

110

Octal

5

2

7

7

.

6

∴ (ABF.C)

_{16}= (5277.6)_{8}Conversion of the Octal number 576 to Decimal.

(576)8

=

(5 × 64)

+

(7 × 8)

+

(6 × 1)

=

320

+

56

+

6

=

382

∴ (576)

_{8}= (382)_{10}Conversion of the Hexadecimal number A5C1 to Decimal.

(A5C1)16

=

(A × 16

^{3})+

(5 × 16

^{2})+

(C × 16

^{1})+

(1 × 16

^{0})=

(10 × 4096)

+

(5 × 256)

+

(12 × 16)

+

(1 × 1)

=

40960

+

1280

+

192

+

1

=

42433

∴ (A5C1)

_{16}= (42433)_{10}